What is the surface area of a rectangular prism whose dimensions are 334 dm×412 dm×5 dm in square decimeters?

Answer 1

The surface area of a rectangular prism is given by the formula:

Surface Area = 2lw + 2lh + 2wh

Where l, w, and h are the length, width, and height of the prism respectively.

Given:
Length (l) = 334 dm
Width (w) = 412 dm
Height (h) = 5 dm

Substitute these values into the formula:

Surface Area = 2(334)(412) + 2(334)(5) + 2(412)(5)
Surface Area = 274648 + 3340 + 2060
Surface Area = 280,048 square decimeters

Therefore, the surface area of the rectangular prism is 280,048 square decimeters.