Asked by Shinobi
In the diagram below of triangle I, J, KIJK, LL is the midpoint of start overline, I, K, end overline
IK
and MM is the midpoint of start overline, J, K, end overline
JK
. If L, M, equals, 8, x, minus, 53LM=8x−53, and I, J, equals, minus, 26, plus, 6, xIJ=−26+6x, what is the measure of start overline, L, M, end overline
LM
?
IK
and MM is the midpoint of start overline, J, K, end overline
JK
. If L, M, equals, 8, x, minus, 53LM=8x−53, and I, J, equals, minus, 26, plus, 6, xIJ=−26+6x, what is the measure of start overline, L, M, end overline
LM
?
Answers
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Answered by
GPT 3.5
Since LL is the midpoint of start overline, I, K, end overline IK, we know that LL = 1/2(IK). Similarly, MM is the midpoint of start overline, J, K, end overline JK, so MM = 1/2(JK).
We are given that LM = 8x - 53 and IJ = -26 + 6x.
Since LL = 1/2(IK), we have LL = 1/2(IK) = 1/2(IJ + JK) = 1/2(IJ + MM), then
8x - 53 = 1/2(-26 + 6x + MM).
We know that MM = 1/2(JK), so MM = 1/2(IJ + JK). Since IJ = -26 + 6x, then JK = MM = 1/2(IJ) = 1/2(-26 + 6x) = -13 + 3x.
Substitute this into the equation above:
8x - 53 = 1/2(-26 + 6x + (-13 + 3x))
8x - 53 = 1/2(-39 + 9x)
16x - 106 = -39 + 9x
7x = 67
x = 67/7 = 9.57
So, the measure of LM is LM = 8(9.57) - 53 = 20.56.
We are given that LM = 8x - 53 and IJ = -26 + 6x.
Since LL = 1/2(IK), we have LL = 1/2(IK) = 1/2(IJ + JK) = 1/2(IJ + MM), then
8x - 53 = 1/2(-26 + 6x + MM).
We know that MM = 1/2(JK), so MM = 1/2(IJ + JK). Since IJ = -26 + 6x, then JK = MM = 1/2(IJ) = 1/2(-26 + 6x) = -13 + 3x.
Substitute this into the equation above:
8x - 53 = 1/2(-26 + 6x + (-13 + 3x))
8x - 53 = 1/2(-39 + 9x)
16x - 106 = -39 + 9x
7x = 67
x = 67/7 = 9.57
So, the measure of LM is LM = 8(9.57) - 53 = 20.56.
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