Question

Solve the system of equations.

3x - 4y = 40
5x - 5y = 55


(8,-3)
(4,-7)
(18, 7)
(14, 3)

Answer 1

To solve the system of equations:

3x - 4y = 40
5x - 5y = 55

We can solve this system using the substitution method or the elimination method. Let's use the elimination method to solve this system.

3x - 4y = 40
5x - 5y = 55

First, we'll multiply the first equation by 5 and the second equation by 3 to make the coefficients of y the same:

15x - 20y = 200
15x - 15y = 165

Now, we'll subtract the second equation from the first equation:

-5y = 35
y = -7

Now that we know the value of y, we can substitute it back into one of the original equations to solve for x. Let's use the first equation:

3x - 4(-7) = 40
3x + 28 = 40
3x = 12
x = 4

Therefore, the solution to the system of equations is x = 4, y = -7, which corresponds to the point (4,-7).

So, the answer is:
(4, -7)