Question

A store is having a three-day sale. On the first day of the sale, the price of an item is reduced by 10% from its regular price.
Each day of the sale after the first day, the price of each sale item is reduced to equal 90% of its price from the previous day.

One sale item has an original price of $10.00.

What is the price for the item on the 3rd day of the sale?

Answer 1

On the first day of the sale, the price of the item is reduced by 10%, so it becomes $10.00 * 0.90 = $9.00.

On the second day of the sale, the price of the item is reduced by 10% again, so it becomes $9.00 * 0.90 = $8.10.

On the third day of the sale, the price of the item is reduced by 10% one more time, so it becomes $8.10 * 0.90 = $7.29.

Therefore, the price for the item on the 3rd day of the sale is $7.29.

Answer 2

U sure

Answer 3

Let's calculate again:

Original price of the item: $10.00

First day of the sale: 10% off -> $10.00 * 0.90 = $9.00

Second day of the sale: 10% off -> $9.00 * 0.90 = $8.10

Third day of the sale: 10% off -> $8.10 * 0.90 = $7.29

Therefore, the price for the item on the 3rd day of the sale is indeed $7.29.

Answer 4

U sure..

Answer 5

Let's verify one more time:

Original price of the item: $10.00

Day 1: 10% off -> $10.00 * 0.90 = $9.00
Day 2: 10% off -> $9.00 * 0.90 = $8.10
Day 3: 10% off -> $8.10 * 0.90 = $7.29

Based on the calculations, the price for the item on the 3rd day of the sale is indeed $7.29.