To write the equation y−2=32(x+2) in slope-intercept form, we need to solve for y.
First, distribute the 32 on the right side of the equation:
y - 2 = 32x + 64
Next, add 2 to both sides of the equation to isolate y:
y = 32x + 66
Therefore, the equation y−2=32(x+2) in slope-intercept form is y = 32x + 66.
Write y−2=32(x+2) in slope-intercept form. What’s the answer
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