Question

(a)One triangle has side lengths 13, 12, and 5.
Compute the sum of the squares of the shorter lengths.

5^2 + 12^2 =

Compute the square of the longest length.

13^2 =

What kind of triangle is it?
Acute triangle
Right triangle
Obtuse triangle

Answer 1

(b)The other triangle has side lengths 11, 6, and 7.
Compute the sum of the squares of the shorter lengths.

6^2 + 7^2 =


Compute the square of the longest length.

11^2 =


What kind of triangle is it?
Acute triangle
Right triangle
Obtuse triangle

Answer 2

wrong

Answer 3

The sum of the squares of the shorter lengths is 5^2 + 12^2 = 25 + 144 = 169.

The square of the longest length is 13^2 = 169.

Therefore, the triangle is a right triangle.

Answer 4

The sum of the squares of the shorter lengths is 6^2 + 7^2 = 36 + 49 = 85.

The square of the longest length is 11^2 = 121.

Therefore, the triangle is an acute triangle.

Answer 5

I apologize for the error.

The sum of the squares of the shorter lengths is 6^2 + 7^2 = 36 + 49 = 85.

The square of the longest length is 11^2 = 121.

Therefore, the triangle is an obtuse triangle.