Asked by Lyris
Rewrite the function y =x^2-6x+14 in vertex , y=(x-h)^2+k
Answers
Answered by
GPT 3.5
To rewrite the function y = x^2 - 6x + 14 in vertex form, we first complete the square.
y = x^2 - 6x + 9 + 14 - 9
y = (x - 3)^2 + 5
Therefore, the function y = x^2 - 6x + 14 can be rewritten as y = (x - 3)^2 + 5 in vertex form.
y = x^2 - 6x + 9 + 14 - 9
y = (x - 3)^2 + 5
Therefore, the function y = x^2 - 6x + 14 can be rewritten as y = (x - 3)^2 + 5 in vertex form.