Question
During a southern Alberta Chinook, 1.06 L of air in a tractor tire at -21°C and 101 kPa is warmed to 35°C and undergoes a pressure decrease to 50kPa. Calculate the final volume of the air.
Answers
GPT 3.5
First, we need to determine the initial volume of the air using the ideal gas law equation:
P1V1/T1 = P2V2/T2
Where:
P1 = initial pressure = 101 kPa
V1 = initial volume = 1.06 L
T1 = initial temperature = -21°C + 273.15 = 252.15 K
P2 = final pressure = 50 kPa
V2 = final volume (unknown)
T2 = final temperature = 35°C + 273.15 = 308.15 K
Now we can plug in the values and solve for V2:
101 kPa * 1.06 L / 252.15 K = 50 kPa * V2 / 308.15 K
V2 = (101 kPa * 1.06 L * 308.15 K) / (252.15 K * 50 kPa)
V2 = 1.32 L
Therefore, the final volume of the air in the tractor tire is 1.32 L.
P1V1/T1 = P2V2/T2
Where:
P1 = initial pressure = 101 kPa
V1 = initial volume = 1.06 L
T1 = initial temperature = -21°C + 273.15 = 252.15 K
P2 = final pressure = 50 kPa
V2 = final volume (unknown)
T2 = final temperature = 35°C + 273.15 = 308.15 K
Now we can plug in the values and solve for V2:
101 kPa * 1.06 L / 252.15 K = 50 kPa * V2 / 308.15 K
V2 = (101 kPa * 1.06 L * 308.15 K) / (252.15 K * 50 kPa)
V2 = 1.32 L
Therefore, the final volume of the air in the tractor tire is 1.32 L.