Asked by frank

A uniform electric field of 500. V/m is directed in the negative x direction. A +15ìC charge moves from the origin to the point (x,y) = (20.0 cm, 50.0 cm). (a) what was the change in the potential energy of this charge? (b) Through what potential difference did the charge move?

This is how i worked it out and it is incorrect.Please tell me what step is incorrect.
(15x10^6C)(500N/C)[(0.2)+0]
ÄP.E= .0015J

Answers

Answered by bobpursley
Is the sign right on the .2 meters? The charge went against the field. Otherwise, it is ok.
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