Since spinning the spinner twice are independent events, the probability of landing on a 7 and then landing on a 5 is the product of the individual probabilities.
The spinner has 6 equal sections, numbered 1 to 6. The probability of landing on a 7 is 0, as it's not on the spinner. The probability of landing on a 5 is 1/6, as there is only 1 section with a 5 out of the 6 total sections.
Therefore, the probability of landing on a 7 and then landing on a 5 is 0 * 1/6 = 0.
You spin the spinner twice.
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What is the probability of landing on a 7 and then landing on a 5?
Write your answer as a fraction or whole number.
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1 answer