If I understand you, the sides of the pyramid consist of equilateral triangle of sides 6 units.
So a line d from the vertex bisecting the triangle would make the base 3 and the hypotenuse 6 in the new triangle.
let the height be h
h^2 + 3^2 = 6^2
Can you finish it ?
I have a pic of a right square pyramid with equilateral triangular faces with each side of the triangle measuring 6 in. i have a line "d" intersecting one of the triangles making 2 right angle triangles. Using the pythagoream theory- how do I find the distance d?
I know a2 +b2=C2, but isn't it already known? Isn't the length of d just 6? Please help. Thanks,
1 answer
1 answer