x = 6y - 3
We can substitute x = 6y - 3 into the second equation:
2(6y - 3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13
19y = 19
y = 1
Now, we can substitute y = 1 back into the first equation to solve for x:
x = 6(1) - 3
x = 6 - 3
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 1.
Solve the system of equations.
x = 6y - 3
2x + 7y = 13 (1 point)
1 answer