9.03g og magnesium combine completely with 3.48g of nitrogen.

Question

Calculate the percent composition

Answer 1

To calculate the percent composition, we first need to calculate the molar mass of Mg and N.

Molar mass of Mg = 24.305 g/mol
Molar mass of N = 14.007 g/mol

Next, we need to find the moles of Mg and N in the given weights.

Moles of Mg = 9.03g / 24.305 g/mol = 0.371 moles
Moles of N = 3.48g / 14.007 g/mol = 0.248 moles

Now, we can calculate the percent composition of Mg and N in the compound.

Percent composition of Mg = (moles of Mg / total moles in compound) x 100
= (0.371 moles / (0.371 moles + 0.248 moles)) x 100
= 60.0%

Percent composition of N = (moles of N / total moles in compound) x 100
= (0.248 moles / (0.371 moles + 0.248 moles)) x 100
= 40.0%

Therefore, the compound has a percent composition of 60.0% magnesium and 40.0% nitrogen.