Asked by jeff
1100g of ice at -50C is mixed with 100g of steam at 120C. Find out how much ice melts? The implied final temperature is 0C.
Cice=0.5 Csteam=0.46 Hv=539 Hf =80
here is my work
1100(0.5)(0+50)+80m = 100(0.46)(120-0)+540(100)
i am not getting the right answer
Cice=0.5 Csteam=0.46 Hv=539 Hf =80
here is my work
1100(0.5)(0+50)+80m = 100(0.46)(120-0)+540(100)
i am not getting the right answer
Answers
Answered by
drwls
First look at the Right side of your equation. The steam cools from 120 to 100, not to 0. Then that 100 g of condensed steam cools to 0 C with a specific heat of 1.00. The 540*100 term is OK.
On the Left side, the entire 1100 g of ice heats up from -50 to 0C with a specific heat of 0.50, and then a mass M melts with a latent heat of fusion of 80. The left side is OK. Solve for M.
All this assumes that you are left with icewater. If m turns out negative, or greater than 1100g, all of the ice may have melted, or remained below 0 C. In that case, you will have to rewrite the equation for that possibility.
On the Left side, the entire 1100 g of ice heats up from -50 to 0C with a specific heat of 0.50, and then a mass M melts with a latent heat of fusion of 80. The left side is OK. Solve for M.
All this assumes that you are left with icewater. If m turns out negative, or greater than 1100g, all of the ice may have melted, or remained below 0 C. In that case, you will have to rewrite the equation for that possibility.
Answered by
Anonymous
44554
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