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Given the coordinates (9,−2), (9,−11), (15,−4), and (15,−13), what is the length of each of the two longest sides of the quadri...Asked by Terrariareti GD YT
Given the coordinates (9,−2) , (9,−11) , (15,−4) , and (15,−13) , what is the length of each of the two longest sides of the quadrilateral, in cm?
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Answered by
GPT 3.5
To find the length of each of the two longest sides of the quadrilateral, we first need to calculate the distance between each pair of points.
Using the distance formula:
Distance = √((x2-x1)^2 + (y2-y1)^2)
1. Between points (9, -2) and (15, -4):
Distance = √((15-9)^2 + (-4-(-2))^2)
Distance = √(6^2 + (-2)^2)
Distance = √(36 + 4)
Distance = √40
Distance ≈ 6.32 cm
2. Between points (9, -11) and (15, -13):
Distance = √((15-9)^2 + (-13-(-11))^2)
Distance = √(6^2 + (-13+11)^2)
Distance = √(36 + 2^2)
Distance = √(36 + 4)
Distance = √40
Distance ≈ 6.32 cm
3. Between points (9, -2) and (9, -11):
Distance = √(0^2 + (-11-(-2))^2)
Distance = √(0 + (-9)^2)
Distance = √(0 + 81)
Distance = √81
Distance = 9 cm
4. Between points (15, -4) and (15, -13):
Distance = √(0^2 + (-13-(-4))^2)
Distance = √(0 + (-13+4)^2)
Distance = √(0 + (-9)^2)
Distance = √81
Distance = 9 cm
Therefore, the two longest sides of the quadrilateral are 9 cm each.
Using the distance formula:
Distance = √((x2-x1)^2 + (y2-y1)^2)
1. Between points (9, -2) and (15, -4):
Distance = √((15-9)^2 + (-4-(-2))^2)
Distance = √(6^2 + (-2)^2)
Distance = √(36 + 4)
Distance = √40
Distance ≈ 6.32 cm
2. Between points (9, -11) and (15, -13):
Distance = √((15-9)^2 + (-13-(-11))^2)
Distance = √(6^2 + (-13+11)^2)
Distance = √(36 + 2^2)
Distance = √(36 + 4)
Distance = √40
Distance ≈ 6.32 cm
3. Between points (9, -2) and (9, -11):
Distance = √(0^2 + (-11-(-2))^2)
Distance = √(0 + (-9)^2)
Distance = √(0 + 81)
Distance = √81
Distance = 9 cm
4. Between points (15, -4) and (15, -13):
Distance = √(0^2 + (-13-(-4))^2)
Distance = √(0 + (-13+4)^2)
Distance = √(0 + (-9)^2)
Distance = √81
Distance = 9 cm
Therefore, the two longest sides of the quadrilateral are 9 cm each.
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