To solve this system of equations, we can use the method of substitution or elimination.
Let's solve by substitution.
First, let's rearrange the first equation to solve for x:
4x - 6y = -48
4x = 6y - 48
x = (6y - 48) / 4
x = (3/2)y - 12
Now substitute this expression for x into the second equation:
-2((3/2)y - 12) + 4y = 30
-3y + 24 + 4y = 30
y + 24 = 30
y = 6
Now that we have found the value for y, we can substitute it back into one of the original equations to solve for x:
4x - 6(6) = -48
4x - 36 = -48
4x = -12
x = -3
Therefore, the solution to the system of equations is x = -3 and y = 6.
4x-6y=-48
-2x+4y=30
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