The vertex of the equation f(x) = -x^2 + 6 is given by the coordinates of the point (h, k) where h is the x-coordinate and k is the y-coordinate of the vertex.
To find the vertex, we first need to rewrite the equation in vertex form, which is given by f(x) = a(x - h)^2 + k.
In this case, a = -1, h = 0, and k = 6. So, the vertex form of the equation can be written as f(x) = -(x - 0)^2 + 6, which simplifies to f(x) = -x^2 + 6.
Therefore, the vertex of the equation f(x) = -x^2 + 6 is (0, 6).
What is the vertex of the equation f (x) = -x^2 + 6?
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1 answer