Solution:
To solve `2x^{2}-5x-3=0`, we can use the quadratic formula:
x = (-(-5) ± √((-5)^2 - 4 * 2 * -3)) / (2 * 2)
x = (5 ± √(25 + 24)) / 4
x = (5 ± √49) / 4
x = (5 ± 7) / 4
Therefore, the solutions are:
x1 = (5 + 7) / 4 = 12 / 4 = 3
x2 = (5 - 7) / 4 = -2 / 4 = -0.5
So the solutions are x = 3 and x = -0.5
(Graph of y=2x^{2}-5x-3 will be shown.)
1) Solve `2x^{2}-5x-3=0`and enter solutions below.
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