Let the coordinates of the point be (x, y).
Given that the distance of the point from the x-axis is 4 times its distance from the y-axis, we have the following relationship:
√(x^2 + y^2) = 4√(x^2 + y^2)
Simplifying, we get:
x^2 + y^2 = 16x^2 + 16y^2
-15x^2 - 15y^2 = 0
x^2 + y^2 = 0
This is the equation of the locus of the point, which is a point at the origin (0,0).
A point moves such that its distance from the x-axis is 4 times it's distance from the y axis.Find the equation of the locus of point.
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