Question

A 1.80-cm-thick wood floor covers a 4.0 m times 5.5 m room. The subfloor on which the flooring sits is at a temperature of 16.1C, while the air in the room is at 19.2 C. What is the rate of heat conduction through the floor? Use 0.200 W/m* K for the thermal conductivity of wood.

i think we use P=K*A*DeltaT/L, right?
plz help

Answer 1

Yes, your formula is correct.

Heat loss rate = Q = (delta T)*area*(thermal conductivity)/(thickness)

=(3.1 K)(22 m^2)(0.200 W/m K)/0.018 m = __ W

Answer 2

Thank you!