Question

What are the steps to solving x^2-10x-12=0?

Answer 1

no its not

Answer 2

can you solve in standard form

Answer 3

To solve the quadratic equation x^2-10x-12=0, follow these steps:

1. Write the equation in standard form: x^2-10x-12=0.

2. Factor the quadratic equation, if possible. In this case, the equation can be factored as (x-12)(x+2)=0.

3. Set each factor equal to zero and solve for x:
- x-12=0 => x=12
- x+2=0 => x=-2

4. The solutions to the equation x^2-10x-12=0 are x=12 and x=-2.

Answer 4

I apologize for the mistake in my previous response. Let's solve the quadratic equation x^2-10x-12=0 correctly:

1. Write the equation in standard form: x^2-10x-12=0.

2. Use the quadratic formula to solve for x:
x = (-b ± sqrt(b^2 - 4ac)) / 2a

In this equation, a = 1, b = -10, and c = -12.

3. Substitute the values of a, b, and c into the formula:
x = (10 ± sqrt((-10)^2 - 4*1*(-12))) / 2*1
x = (10 ± sqrt(100 + 48)) / 2
x = (10 ± sqrt(148)) / 2

4. Simplify the expression under the square root:
x = (10 ± sqrt(4*37)) / 2
x = (10 ± 2sqrt(37)) / 2
x = 5 ± sqrt(37)

5. The solutions to the equation x^2-10x-12=0 are x = 5 + sqrt(37) and x = 5 - sqrt(37).

Answer 5

Yes, I can solve in standard form. Let's continue the solution:

1. Write the equation in standard form: x^2-10x-12=0.

2. To solve this quadratic equation, we can use the quadratic formula:
The quadratic formula is: x = (-b ± sqrt(b^2 - 4ac)) / 2a

In our equation, a = 1, b = -10, and c = -12.

3. Substitute the values of a, b, and c into the quadratic formula:
x = (10 ± sqrt((-10)^2 - 4*1*(-12))) / 2*1
x = (10 ± sqrt(100 + 48)) / 2
x = (10 ± sqrt(148)) / 2
x = (10 ± 2sqrt(37)) / 2
x = 5 ± sqrt(37)

4. Therefore, the solutions to the equation x^2-10x-12=0 are x = 5 + sqrt(37) and x = 5 - sqrt(37) in standard form.