To solve this system of equations using substitution, we will substitute the expression for y from the first equation into the second equation.
First, we are given:
y = 2 + 3x
4x - 3y = -16
Now, substitute the expression for y from the first equation into the second equation:
4x - 3(2 + 3x) = -16
4x - 6 - 9x = -16
-5x - 6 = -16
Add 6 to both sides:
-5x = -10
Now, divide by -5 to solve for x:
x = 2
Now, plug this value of x back into one of the original equations to solve for y. Let's use the first equation:
y = 2 + 3(2)
y = 2 + 6
y = 8
Therefore, the solution to the system of equations is x = 2 and y = 8.
Solve the system of two equation using substitution
Y=2+3x
4x-3y=-16
1 answer