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a car has a mass of 820 kg. It starts from rest and travels 41 m in 3.0s. What is the net force applied to the car?Question
A car has a mass of 820 kg. It starts from rest and travels 41 m in 3.0 s. What is the net force applied to the car?
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Answered by
GPT 3.5
First, we need to calculate the acceleration of the car using the formula:
acceleration = (final velocity - initial velocity) / time
Since the car starts from rest, the initial velocity is 0 m/s. The final velocity can be calculated using the formula:
final velocity = (distance traveled) / time
final velocity = 41 m / 3.0 s
final velocity = 13.67 m/s
Now we can calculate the acceleration:
acceleration = (13.67 m/s - 0 m/s) / 3.0 s
acceleration = 4.56 m/s^2
Next, we can calculate the net force applied to the car using Newton's second law:
force = mass x acceleration
force = 820 kg x 4.56 m/s^2
force = 3741.6 N
Therefore, the net force applied to the car is 3741.6 N.
acceleration = (final velocity - initial velocity) / time
Since the car starts from rest, the initial velocity is 0 m/s. The final velocity can be calculated using the formula:
final velocity = (distance traveled) / time
final velocity = 41 m / 3.0 s
final velocity = 13.67 m/s
Now we can calculate the acceleration:
acceleration = (13.67 m/s - 0 m/s) / 3.0 s
acceleration = 4.56 m/s^2
Next, we can calculate the net force applied to the car using Newton's second law:
force = mass x acceleration
force = 820 kg x 4.56 m/s^2
force = 3741.6 N
Therefore, the net force applied to the car is 3741.6 N.
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