To solve this system of equations, we can use either the substitution or elimination method. Let's use the elimination method.
First, we will multiply the first equation by 2 and the second equation by 3 to make the coefficients of Y equal:
-12X + 4Y = -64
12X + 9Y = -27
Now, add the two equations together to eliminate the X term:
0 + 13Y = -91
13Y = -91
Y = -7
Now that we have found the value of Y, we can substitute it back into one of the original equations to solve for X. Let's use the first equation:
-6X + 2(-7) = -32
-6X - 14 = -32
-6X = -18
X = 3
Therefore, the solution to the system of equations is X = 3 and Y = -7.
Solve the system of equations
Negative 6X plus 2Y equals -32
4X plus 3Y equals -9
1 answer