To solve this system of equations, we will use the method of substitution or elimination.
Given equations:
1) 5X - 4Y = -44
2) -X + 3Y = 22
From equation 2, we can solve for X in terms of Y:
-X = 22 - 3Y
X = 3Y - 22
Now, substitute the value of X into equation 1:
5(3Y - 22) - 4Y = -44
15Y - 110 - 4Y = -44
11Y - 110 = -44
11Y = 66
Y = 6
Now, substitute the value of Y back into the equation for X:
X = 3(6) - 22
X = 18 - 22
X = -4
Therefore, the solutions to the system of equations are X = -4 and Y = 6.
Solve the system of equations
5X minus 4Y equals -44
Negative X plus 3Y equals 22
1 answer