To solve this system of linear equations using elimination by multiplication, we need to first make the coefficients of either the x or y terms the same in both equations.
First, let's rewrite the equations in standard form:
1) x + 4y = -4
2) 3x + 5y = -3
Next, we'll multiply the first equation by 3 and the second equation by -1 to make the coefficients of the x terms equal:
3(x + 4y) = 3(-4)
-1(3x + 5y) = -1(-3)
Which gives us:
3x + 12y = -12
-3x - 5y = 3
Now, we can add these two equations together to eliminate the x terms:
(3x + 12y) + (-3x - 5y) = -12 + 3
7y = -9
y = -9/7
Now that we have solved for y, we can substitute this value back into one of the original equations to solve for x. Let's use the first equation:
x + 4(-9/7) = -4
x - 36/7 = -4
x = -4 + 36/7
x = -28/7 + 36/7
x = 8/7
Therefore, the solution to the system of linear equations is x = 8/7 and y = -9/7.
Solve the system of linear equations using elimination by multiplication. x + 4y = -4
3x = -5y = -3
1 answer
1 answer