Asked by Chelsea
I need help solving 3x-1/x+5 + 43/x^2-25= 3x+1/x-5
Answers
Answered by
bobpursley
Your non-use of parenthesis is frustrating.
I assume you mean this:
(3x-1)/(x+5) + 43/(x^2-25)= (3x+1)/(x-5)
remember that x^2-25 is (x-5)(x+5)
now multiply both sides by
(x-5)(x+5)
I assume you mean this:
(3x-1)/(x+5) + 43/(x^2-25)= (3x+1)/(x-5)
remember that x^2-25 is (x-5)(x+5)
now multiply both sides by
(x-5)(x+5)
Answered by
Chelsea
sorry instead here it's
(3x-1)/(x+5) +(32)/(x^2-25)=(3x+1
)/(x-5)
yes I know that it will factor out to be (X+5)(x-5) but the thing is isn't 3x-1 only multiply by 1 since it already have (X+5) as its denominator?
(3x-1)/(x+5) +(32)/(x^2-25)=(3x+1
)/(x-5)
yes I know that it will factor out to be (X+5)(x-5) but the thing is isn't 3x-1 only multiply by 1 since it already have (X+5) as its denominator?
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