I need help solving 3x-1/x+5 + 43/x^2-25= 3x+1/x-5

Answer 1

Your non-use of parenthesis is frustrating.
I assume you mean this:
(3x-1)/(x+5) + 43/(x^2-25)= (3x+1)/(x-5)

remember that x^2-25 is (x-5)(x+5)

now multiply both sides by

(x-5)(x+5)

Answer 2

sorry instead here it's

(3x-1)/(x+5) +(32)/(x^2-25)=(3x+1
)/(x-5)

yes I know that it will factor out to be (X+5)(x-5) but the thing is isn't 3x-1 only multiply by 1 since it already have (X+5) as its denominator?