Question
Which numbers 1, 2, and 3 is a solution of 2x + 1>7
Answers
Answer
What number is not part of the solution set for z/5 =7
Answered by
GPT 3.5
To determine if a number is a solution of the inequality 2x + 1 > 7, we can plug in the number into the inequality and see if it is true.
Let's test each number:
1) For x = 1:
2(1) + 1 = 2 + 1 = 3
3 is not greater than 7, so x = 1 is not a solution.
2) For x = 2:
2(2) + 1 = 4 + 1 = 5
5 is not greater than 7, so x = 2 is not a solution.
3) For x = 3:
2(3) + 1 = 6 + 1 = 7
7 is not greater than 7, so x = 3 is not a solution.
Therefore, none of the numbers 1, 2, or 3 are solutions of the inequality 2x + 1 > 7.
Let's test each number:
1) For x = 1:
2(1) + 1 = 2 + 1 = 3
3 is not greater than 7, so x = 1 is not a solution.
2) For x = 2:
2(2) + 1 = 4 + 1 = 5
5 is not greater than 7, so x = 2 is not a solution.
3) For x = 3:
2(3) + 1 = 6 + 1 = 7
7 is not greater than 7, so x = 3 is not a solution.
Therefore, none of the numbers 1, 2, or 3 are solutions of the inequality 2x + 1 > 7.
Answered by
GPT 3.5
To find out which number is not part of the solution set for the equation z/5 = 7, we can solve the equation for z and check which number does not satisfy the equation.
z/5 = 7
Multiplying by 5 on both sides of the equation to isolate z:
z = 7 * 5
z = 35
Therefore, the solution for the equation z/5 = 7 is z = 35. So, the number that is not part of the solution set for this equation is any number other than 35.
z/5 = 7
Multiplying by 5 on both sides of the equation to isolate z:
z = 7 * 5
z = 35
Therefore, the solution for the equation z/5 = 7 is z = 35. So, the number that is not part of the solution set for this equation is any number other than 35.
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