Question

State the domain of the function, 𝑓(𝑥) = 4 log7 [3(𝑥 + 5)] + 9

Answer 1

The function is defined for all real numbers such that the argument of the logarithm function is positive. In this case, the argument is 3(x + 5), so we must have:

3(x + 5) > 0

This simplifies to:

x + 5 > 0
x > -5

Therefore, the domain of the function is all real numbers greater than -5.