Solve the system of two equations using substitution.

Question

y=2+3x
4x−3y=−16

Answer 1

First, we will solve the first equation for y:

y = 2 + 3x

Next, we will substitute this expression for y into the second equation:

4x - 3(2 + 3x) = -16
4x - 6 - 9x = -16
-5x - 6 = -16
-5x = -10
x = 2

Now that we have found the value of x, we can substitute it back into the first equation to solve for y:

y = 2 + 3(2)
y = 2 + 6
y = 8

Therefore, the solution to the system of equations is x = 2 and y = 8.