Not quite sure I understand the question.
If we go to the Gibb's free energy equation:
delta G = delta H - (T)(delta S)
where T is the temperature in kelvin
Remember that a more negative value of delta g is more spontaneous, and a large positive value of delta g is less spontaneous.
since both H and S are negative:
delta G = (-H) - (T)(-S)
delta G = (-H) + (T)(S)
thus, the larger the value of T, the more positive the delta G... the LESS spontaneous...
Is this what you are after?
CH2=CH2 +H2O <--> CH3-CH2-OH
Delta H = -10.6 kcal/mol
Delta S = -30.3 cal/Kmol
why is delta S a negative value?
1 answer