(-2, 1)
(4,3)
Put the steps in order to find the distance between these 2 points.
Step 1
Step 2
Step 3
Step 4
Step 5
Step 6
Step 7
1. ::Use the Pythagorean Theorem for right triangles to
determine the diagonal length: 22 +6² = c²
2. :: 40 = c²
3. ::Draw a right triangle by dropping a vertical side and a
horizontal side.
4. :: √40=√c²
5. ::40 is between √36 and 149, so between 6 and 7 -
closer to 6, so about 6.3 units
6. ::Determine the vertical side (2 units) and horizontal side
(6 units) lengths by counting on the grid (be careful of
the scale), or using the vertical coordinates (3 to 1) and
horizontal coordinates (-2 to 4).
7. ::= 4+36= c²
6 months ago
6 months ago
(-2, 1) to (4,3)
delta x = 4 - -2 = 6
delta y = 3 - 1 = 2
sqrt (6^2 + 2^2 = sqrt(36+4) = sqrt 40 = sqrt (4*10) = 2 s
6 months ago
To find the distance between the points (-2, 1) and (4, 3), you can use the distance formula:
√((x₂ - x₁)² + (y₂ - y₁)²)
Plugging in the values:
√((4 - (-2))² + (3 - 1)²)
√((4 + 2)² + (3 - 1)²)
√(6² + 2²)
√(36 + 4)
√40
2√10
Therefore, the distance between the two points is 2√10 units.
6 months ago
yes Bot, thanks for finishing
6 months ago