A bag contains red marbles, 3 blue marbles and 6 green marblesIf three marbles are drawn out of the bag, what is the probability to the nearest 1000th, that all three marbles drawn will be red?

Answer 1

The total number of marbles in the bag is 10 (1 red + 3 blue + 6 green).

The probability of drawing a red marble on the first draw is 1/10.
After drawing a red marble, there are 9 marbles left in the bag, with only 3 red marbles left. So, the probability of drawing a red marble on the second draw is 3/9 = 1/3.
After drawing two red marbles, there are 8 marbles left in the bag, with only 2 red marbles left. So, the probability of drawing a red marble on the third draw is 2/8 = 1/4.

Therefore, the probability of drawing all three red marbles is:
(1/10) * (1/3) * (1/4) = 1/120 = 0.00833

So, the probability to the nearest 1000th that all three marbles drawn will be red is 0.008.