To find the horizontal distance the paratrooper lands from his initial position in the sky, we can use the Pythagorean theorem.
Let x be the horizontal distance the paratrooper lands from his initial position in the sky.
Using the slope formula (slope = rise / run), we can find the vertical distance the paratrooper falls:
6.5 = vertical distance / 1
vertical distance = 6.5 meters
Now, we can use the Pythagorean theorem to find the horizontal distance:
(2,795)^2 = x^2 + (6.5)^2
7,807,025 = x^2 + 42.25
x^2 = 7,807,025 - 42.25
x^2 = 7,806,982.75
x ≈ √7,806,982.75
x ≈ 2,794.03
Therefore, the paratrooper lands approximately 2,794.03 meters horizontally across the ground from his initial position in the sky.
A paratrooper falls to the ground along a diagonal line. His fall begins 2, 795 meters above the ground, and the line he follows has a slope of 6.5. That is, he falls 6.5 meters vertically for every 1 meter he moves across horizontally.
How far horizontally across the ground does he land from his initial position in the sky?
1 answer