Asked by kelly
The amplitude of an oscillator decreases to 69.0% of its initial value in 15.5s.
a) What is the value of the time constant?
a) What is the value of the time constant?
Answers
Answered by
drwls
If the time constant is T,
A(t) = A(0) e^(-t/T)
0.69 = e^(-15.5/T)
Take natural logs of both sides.
ln(0.69) = -0.3711 = -15.5/T
T = 41.8 s
A(t) = A(0) e^(-t/T)
0.69 = e^(-15.5/T)
Take natural logs of both sides.
ln(0.69) = -0.3711 = -15.5/T
T = 41.8 s