Question
Mia put two gifts in a shipping box, then filled the box with Styrofoam "peanuts".
The dimensions of the shipping box were 12 inches by 5 inches by 5
inches.
One gift was a puzzle cube with a side length of 4 inches.
One gift was a card game that was in a box with dimensions 6 inches by 4 inches by 4 1/2 inches.
What was the volume of the Styrofoam "peanuts" in the shipping box?
The dimensions of the shipping box were 12 inches by 5 inches by 5
inches.
One gift was a puzzle cube with a side length of 4 inches.
One gift was a card game that was in a box with dimensions 6 inches by 4 inches by 4 1/2 inches.
What was the volume of the Styrofoam "peanuts" in the shipping box?
Answers
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Answered by
GPT 3.5
First, calculate the volume of the two gifts:
Volume of puzzle cube = side length^3 = 4^3 = 64 cubic inches
Volume of card game box = length x width x height = 6 x 4 x 4.5 = 108 cubic inches
Total volume of the gifts = 64 + 108 = 172 cubic inches
Next, calculate the volume of the shipping box:
Volume of shipping box = length x width x height = 12 x 5 x 5 = 300 cubic inches
Now, subtract the total volume of the gifts from the volume of the shipping box to find the volume of the Styrofoam "peanuts":
Volume of Styrofoam "peanuts" = 300 - 172 = 128 cubic inches
Therefore, the volume of the Styrofoam "peanuts" in the shipping box is 128 cubic inches.
Volume of puzzle cube = side length^3 = 4^3 = 64 cubic inches
Volume of card game box = length x width x height = 6 x 4 x 4.5 = 108 cubic inches
Total volume of the gifts = 64 + 108 = 172 cubic inches
Next, calculate the volume of the shipping box:
Volume of shipping box = length x width x height = 12 x 5 x 5 = 300 cubic inches
Now, subtract the total volume of the gifts from the volume of the shipping box to find the volume of the Styrofoam "peanuts":
Volume of Styrofoam "peanuts" = 300 - 172 = 128 cubic inches
Therefore, the volume of the Styrofoam "peanuts" in the shipping box is 128 cubic inches.
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