First, find the slope of the line using the coordinates of points A and B:
Slope = (y2 - y1) / (x2 - x1)
Slope = (-1 - 2) / (0 - (-1))
Slope = -3 / 1
Slope = -3
Now that we have the slope, we can use the point-slope form of the equation of a line to find the equation in slope-intercept form:
y - y1 = m(x - x1)
y - 2 = -3(x + 1)
y - 2 = -3x - 3
y = -3x - 1
So, the equation of the line in slope-intercept form is:
y = -3x - 1
A: (-1, 2)
B: (0, -1)
Write the equation of the line in slope-intercept form.
y = __ x + (__)
3 answers
This is equation
y = __ x + (__)
y = __ x + (__)
Apologies for the oversight. The equation of the line in slope-intercept form is:
y = -3x - 1
So, in the given format:
y = -3x - 1
Therefore, the values to fill in the blanks would be: -3 for the slope and -1 for the y-intercept.
y = -3x - 1
So, in the given format:
y = -3x - 1
Therefore, the values to fill in the blanks would be: -3 for the slope and -1 for the y-intercept.