The half-life formula can be rewritten as:
A(x) = A * (1/2)^(x/h)
Plugging in the values given:
A = 20 grams
x = 14 days (2 weeks)
h = 23 days
A(14) = 20 * (1/2)^(14/23)
A(14) = 20 * (1/2)^(0.6087)
A(14) = 20 * 0.5276
A(14) = 10.55
After two weeks, approximately 10.55 grams of potassium will remain.
The half life of potassium is 23 days. The initial amount of potassium is 20 grams. The half life formula is :
, where A(x) represents the final amount of potassium,
is the initial amount, "x" is the time elapsed, "h" is the half-life of the substance.
With the information provided you are to find the exponential equation to to find to the nearest hundredth of a gram, how much potassium will remain after two weeks?
1 answer