Question
How much more kinetic energy does a 6-kilogram bowling ball have when it is rolling at 16 mph (7.1 meters per second) than when it is rolling at 14 mph (6.2 meters per second)?
(1 point)
Responses
35.9 J
35.9 J
266.5 J
266.5 J
151.2 J
151.2 J
1.3 J
(1 point)
Responses
35.9 J
35.9 J
266.5 J
266.5 J
151.2 J
151.2 J
1.3 J
Answers
GPT 3.5
151.2 J
To calculate the kinetic energy, you can use the formula:
KE = (1/2)mv^2
Where KE is the kinetic energy in Joules, m is the mass in kilograms, and v is the velocity in meters per second.
For the first scenario with a velocity of 7.1 m/s and mass of 6 kg:
KE1 = (1/2)(6 kg)(7.1 m/s)^2 = 150.87 J
For the second scenario with a velocity of 6.2 m/s and mass of 6 kg:
KE2 = (1/2)(6 kg)(6.2 m/s)^2 = 0.5(6)(38.44) = 1.5(38.44) = 57.66 J
The difference in kinetic energy is:
ΔKE = KE1 - KE2 = 150.87 J - 57.66 J = 93.21 J
Therefore, the difference between the two scenarios is approximately 93.21 J.
To calculate the kinetic energy, you can use the formula:
KE = (1/2)mv^2
Where KE is the kinetic energy in Joules, m is the mass in kilograms, and v is the velocity in meters per second.
For the first scenario with a velocity of 7.1 m/s and mass of 6 kg:
KE1 = (1/2)(6 kg)(7.1 m/s)^2 = 150.87 J
For the second scenario with a velocity of 6.2 m/s and mass of 6 kg:
KE2 = (1/2)(6 kg)(6.2 m/s)^2 = 0.5(6)(38.44) = 1.5(38.44) = 57.66 J
The difference in kinetic energy is:
ΔKE = KE1 - KE2 = 150.87 J - 57.66 J = 93.21 J
Therefore, the difference between the two scenarios is approximately 93.21 J.