Yes, you are correct. To verify if (-2,6) is a solution to the system of linear equations, we can plug in the values of x and y into the equations and see if they hold true.
For the first equation, x + 2y = 10, when x = -2 and y = 6:
-2 + 2(6) = -2 + 12 = 10
This is not true, so (-2,6) is not a solution to the first equation.
For the second equation, 3x + y = 0, when x = -2 and y = 6:
3(-2) + 6 = -6 + 6 = 0
This is true, so (-2,6) is a solution to the second equation.
Since (-2,6) does not satisfy both equations simultaneously, it is not a solution to the system of linear equations x + 2y = 10 and 3x + y = 0.
is (-2,6) a solution to the system of these linear equations: x+2y =10 and 3x+y=0
My answer is NO, because they do not meet at -2,6.
Am I correct. thanks.
1 answer
1 answer