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A coordinate plane of 4 quadrants shows x and y axes ranging from negative 3 to 3 in increments of 1. A line with arrows at each end intercepts two plotted points, A and B. Point A is plotted at left parenthesis negative 1 comma 2 right parenthesis. Point B is plotted at left parenthesis 0 comma negative 1 right parenthesis.

Write the equation of the line in slope-intercept form.

(1 point)

Answer 1

To find the equation of the line in slope-intercept form, we need to first calculate the slope of the line using the two given points, A(-1, 2) and B(0, -1).

Slope (m) = (y2 - y1) / (x2 - x1)
= (-1 - 2) / (0 - (-1))
= -3 / 1
= -3

Now that we have the slope, we can use one of the points (let's use point A(-1, 2)) to find the y-intercept (b).

y = mx + b
2 = (-3)(-1) + b
2 = 3 + b
b = -1

Therefore, the equation of the line in slope-intercept form is:
y = -3x - 1