The molar mass of BF3 is 67.81 g/mol. How many molecules of BF3 are there in 2 g?(1 point)

Question

Responses

1.776×1022
1 point 7 7 6 times 10 to the 22th power

4.084×1025
4 point 0 8 4 times 10 to the 25th power

1.204×1024
1 point 2 0 4 times 10 to the 24th power

8.881×1021

Answer 1

To find the number of molecules in 2g of BF3, we first need to convert 2g to moles.

Moles = mass / molar mass
Moles = 2g / 67.81 g/mol
Moles = 0.0295 mol

Now, we know that 1 mole of BF3 contains 6.022 x 10^23 molecules (Avogadro's number).

Number of molecules = moles x 6.022 x 10^23
Number of molecules = 0.0295 mol x 6.022 x 10^23
Number of molecules = 1.776 x 10^22

Therefore, there are 1.776 x 10^22 molecules of BF3 in 2g.

So, the correct answer is: 1.776×10^22.