First, we need to calculate the radius of the basketball. The radius is half of the diameter, so for a basketball with a diameter of 9 inches, the radius would be 4.5 inches.
The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius.
Plugging in the values, we get:
V = (4/3) * 3.14 * (4.5)^3
V = (4/3) * 3.14 * 91.125
V ≈ 381.703 cubic inches
Therefore, approximately 381.7 cubic inches of air are needed to fill a basketball with a diameter of 9 inches.
Use the formula for the volume of a sphere to solve the following problem.
How much air is needed to fill a basketball with a diameter of 9 inches? Use 3.14 as an approximation for pi. Round your answer to the nearest tenth.
(1 point)
5 answers
are you sure
I apologize for the error in my previous response. Let's recalculate:
Given:
Diameter of basketball = 9 inches
Radius = 4.5 inches
Using the formula for the volume of a sphere: V = (4/3)πr^3
Plugging in the values:
V = (4/3) * 3.14 * (4.5)^3
V = (4/3) * 3.14 * 91.125
V = 4.188 * 91.125
V ≈ 380.4 cubic inches
Therefore, approximately 380.4 cubic inches of air are needed to fill a basketball with a diameter of 9 inches.
Given:
Diameter of basketball = 9 inches
Radius = 4.5 inches
Using the formula for the volume of a sphere: V = (4/3)πr^3
Plugging in the values:
V = (4/3) * 3.14 * (4.5)^3
V = (4/3) * 3.14 * 91.125
V = 4.188 * 91.125
V ≈ 380.4 cubic inches
Therefore, approximately 380.4 cubic inches of air are needed to fill a basketball with a diameter of 9 inches.
maybe 381.5?
Let's round the answer to the nearest tenth:
380.4 rounded to the nearest tenth is 380.4.
Therefore, approximately 380.4 cubic inches of air are needed to fill a basketball with a diameter of 9 inches.
380.4 rounded to the nearest tenth is 380.4.
Therefore, approximately 380.4 cubic inches of air are needed to fill a basketball with a diameter of 9 inches.