Dertive the equation of the line in slope-intercept form.

(0,2) and (1,-1)

1 answer

To find the equation of the line in slope-intercept form (y = mx + b), we first need to find the slope (m) of the line using the given points (0,2) and (1,-1).

The slope (m) of a line passing through two points (x1, y1) and (x2, y2) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)

Substitute the given points into the formula:
m = (-1 - 2) / (1 - 0)
m = -3 / 1
m = -3

Now that we have found the slope (m) of the line, we can use one of the given points (0,2) to find the y-intercept (b).

Using the point-slope formula (y - y1 = m(x - x1)):
y - 2 = -3(x - 0)
y - 2 = -3x

To get the equation in slope-intercept form (y = mx + b), we need to isolate y:
y = -3x + 2

Therefore, the equation of the line passing through the points (0,2) and (1,-1) in slope-intercept form is y = -3x + 2.