Asked by Sans2000
Use the table to answer the question.
Plant Types | A | B | C | D | E
Number of Seedlings 100 | 140 | 80 | 60 | 40
A farmer conducted an inventory on his two square kilometers of rainforest; the results are in the table. He plans on randomly selecting a seedling to experiment on when he goes back to the forest. What is the probability that he will randomly pick a type B plant? Write your answer in the simplest form of a fraction.
(1 point)
Plant Types | A | B | C | D | E
Number of Seedlings 100 | 140 | 80 | 60 | 40
A farmer conducted an inventory on his two square kilometers of rainforest; the results are in the table. He plans on randomly selecting a seedling to experiment on when he goes back to the forest. What is the probability that he will randomly pick a type B plant? Write your answer in the simplest form of a fraction.
(1 point)
Answers
Answered by
Sans2000
Company X tested its light bulbs to see how long they would last. On a production line, 2,500 bulbs were taken and tested. The department in charge reported that out of 2,500 bulbs, there were 2,200 bulbs that burnt out after more than 1,500 hours of use. Lucy purchased a light bulb from Company X. What is the likelihood that it will burn for more than 1,500 hours? Write your answer in decimal form.
(1 point)
(1 point)
Answered by
Sans2000
The letter tiles C , A , R , E , and S are placed in a box. Without looking, Jorelle picks a letter tile from the box and records the result before placing it back. He repeats the procedure 100 times and observes the following results:
Outcomes | C | A | R | E | S
Frequency | 20 | 25 | 30 | 10 | 15
Based on the observed frequency, what is the probability that Jorelle will pick a letter R ? The answer should be in percent form.
(1 point)
Outcomes | C | A | R | E | S
Frequency | 20 | 25 | 30 | 10 | 15
Based on the observed frequency, what is the probability that Jorelle will pick a letter R ? The answer should be in percent form.
(1 point)
Answered by
Sans2000
Use the table to answer the question.
Outcomes | 2 | 4 | 6 | 8 | 10 | 12
Frequency | 10 | 9 | 6 | 15 | 13 | 8
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What is the largest discrepancy between the experimental and the expected probability of this experiment? The answer needs to be in percent form to the nearest whole number.
(1 point)
Outcomes | 2 | 4 | 6 | 8 | 10 | 12
Frequency | 10 | 9 | 6 | 15 | 13 | 8
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What is the largest discrepancy between the experimental and the expected probability of this experiment? The answer needs to be in percent form to the nearest whole number.
(1 point)
Answered by
Sans2000
That is an incorrect response.
Answered by
Sans2000
Use the table to answer the question.
Outcomes | 2 | 4 | 6 | 8 | 10 | 12
Frequency | 10 | 9 | 6 | 15 | 13 | 8
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What is the smallest discrepancy between the experimental and the expected probability of this experiment? Write your answer in 3 decimal places, rounded to the nearest thousandth.
(1 point)
Outcomes | 2 | 4 | 6 | 8 | 10 | 12
Frequency | 10 | 9 | 6 | 15 | 13 | 8
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What is the smallest discrepancy between the experimental and the expected probability of this experiment? Write your answer in 3 decimal places, rounded to the nearest thousandth.
(1 point)
Answered by
GPT 3.5
The total number of seedlings is 100 + 140 + 80 + 60 + 40 = 420.
The number of type B seedlings is 140.
Therefore, the probability of randomly selecting a type B plant is 140/420 = 1/3.
The number of type B seedlings is 140.
Therefore, the probability of randomly selecting a type B plant is 140/420 = 1/3.
Answered by
GPT 3.5
Out of 2,500 bulbs tested, 2,200 bulbs burnt out after more than 1,500 hours of use.
The probability that a light bulb from Company X will burn for more than 1,500 hours is 2,200/2,500 = 0.88.
Therefore, the likelihood that it will burn for more than 1,500 hours is 0.88.
The probability that a light bulb from Company X will burn for more than 1,500 hours is 2,200/2,500 = 0.88.
Therefore, the likelihood that it will burn for more than 1,500 hours is 0.88.
Answered by
GPT 3.5
The total number of outcomes is 20 + 25 + 30 + 10 + 15 = 100.
The frequency of picking the letter "R" is 30.
The probability of picking the letter "R" is 30/100 = 0.3 or 30%.
Therefore, the probability that Jorelle will pick the letter "R" is 30%.
The frequency of picking the letter "R" is 30.
The probability of picking the letter "R" is 30/100 = 0.3 or 30%.
Therefore, the probability that Jorelle will pick the letter "R" is 30%.
Answered by
GPT 3.5
To find the largest discrepancy between the experimental and the expected probability, we need to calculate the expected probability first.
The total number of outcomes is 10 + 9 + 6 + 15 + 13 + 8 = 61.
The expected probability for each outcome is:
2: 1/6, 4: 1/6, 6: 1/6, 8: 1/6, 10: 1/6, 12: 1/6
Now, let's calculate the expected frequency for each outcome based on the expected probability:
2: (1/6) * 61 = 10.17
4: (1/6) * 61 = 10.17
6: (1/6) * 61 = 10.17
8: (1/6) * 61 = 10.17
10: (1/6) * 61 = 10.17
12: (1/6) * 61 = 10.17
The largest discrepancy occurs for outcome 8:
Experimental frequency: 15
Expected frequency: 10.17
Absolute difference: 15 - 10.17 = 4.83
To find the discrepancy in percent form:
Discrepancy percent = (4.83 / 15) * 100% = 32%
Therefore, the largest discrepancy between the experimental and expected probability in this experiment is approximately 32%.
The total number of outcomes is 10 + 9 + 6 + 15 + 13 + 8 = 61.
The expected probability for each outcome is:
2: 1/6, 4: 1/6, 6: 1/6, 8: 1/6, 10: 1/6, 12: 1/6
Now, let's calculate the expected frequency for each outcome based on the expected probability:
2: (1/6) * 61 = 10.17
4: (1/6) * 61 = 10.17
6: (1/6) * 61 = 10.17
8: (1/6) * 61 = 10.17
10: (1/6) * 61 = 10.17
12: (1/6) * 61 = 10.17
The largest discrepancy occurs for outcome 8:
Experimental frequency: 15
Expected frequency: 10.17
Absolute difference: 15 - 10.17 = 4.83
To find the discrepancy in percent form:
Discrepancy percent = (4.83 / 15) * 100% = 32%
Therefore, the largest discrepancy between the experimental and expected probability in this experiment is approximately 32%.
Answered by
GPT 3.5
I apologize for the error. Let's correct that.
To find the largest discrepancy between the experimental and expected probability, we need to compare the observed frequencies to the expected frequencies based on a fair six-sided die (2, 4, 6, 8, 10, 12).
Expected probability for each outcome is 1/6 as there are 6 possible outcomes.
The expected frequency for each outcome can be calculated as (1/6) * total number of trials (61).
Expected frequency for each outcome:
2: (1/6) * 61 = 10.17
4: (1/6) * 61 = 10.17
6: (1/6) * 61 = 10.17
8: (1/6) * 61 = 10.17
10: (1/6) * 61 = 10.17
12: (1/6) * 61 = 10.17
Now, we compare the observed frequencies to the expected frequencies to find the discrepancies:
For outcome 2: |10 - 10.17| = 0.17
For outcome 4: |9 - 10.17| = 1.17
For outcome 6: |6 - 10.17| = 4.17
For outcome 8: |15 - 10.17| = 4.83
For outcome 10: |13 - 10.17| = 2.83
For outcome 12: |8 - 10.17| = 2.17
The largest discrepancy is for outcome 8 with an absolute difference of 4.83.
Converting this to percent form: (4.83 / 15) * 100% ≈ 32%
Therefore, the correct largest discrepancy between the experimental and expected probability in this experiment is approximately 32%.
To find the largest discrepancy between the experimental and expected probability, we need to compare the observed frequencies to the expected frequencies based on a fair six-sided die (2, 4, 6, 8, 10, 12).
Expected probability for each outcome is 1/6 as there are 6 possible outcomes.
The expected frequency for each outcome can be calculated as (1/6) * total number of trials (61).
Expected frequency for each outcome:
2: (1/6) * 61 = 10.17
4: (1/6) * 61 = 10.17
6: (1/6) * 61 = 10.17
8: (1/6) * 61 = 10.17
10: (1/6) * 61 = 10.17
12: (1/6) * 61 = 10.17
Now, we compare the observed frequencies to the expected frequencies to find the discrepancies:
For outcome 2: |10 - 10.17| = 0.17
For outcome 4: |9 - 10.17| = 1.17
For outcome 6: |6 - 10.17| = 4.17
For outcome 8: |15 - 10.17| = 4.83
For outcome 10: |13 - 10.17| = 2.83
For outcome 12: |8 - 10.17| = 2.17
The largest discrepancy is for outcome 8 with an absolute difference of 4.83.
Converting this to percent form: (4.83 / 15) * 100% ≈ 32%
Therefore, the correct largest discrepancy between the experimental and expected probability in this experiment is approximately 32%.
Answered by
GPT 3.5
To find the smallest discrepancy between the experimental and expected probability in this experiment, we need to compare the observed frequencies to the expected frequencies based on a fair six-sided die (2, 4, 6, 8, 10, 12).
First, let's calculate the total number of trials or outcomes:
Total number of trials = 10 + 9 + 6 + 15 + 13 + 8 = 61
The expected probability for each outcome is 1/6 since there are 6 possible outcomes on a fair six-sided die.
The expected frequency for each outcome will be (1/6) * total number of trials (61) = 10.17.
Now, we compare the observed frequencies to the expected frequencies to find the discrepancies:
Outcome 2:
|Observed Frequency - Expected Frequency| = |10 - 10.17| = 0.17
Outcome 4:
|Observed Frequency - Expected Frequency| = |9 - 10.17| = 1.17
Outcome 6:
|Observed Frequency - Expected Frequency| = |6 - 10.17| = 4.17
Outcome 8:
|Observed Frequency - Expected Frequency| = |15 - 10.17| = 4.83
Outcome 10:
|Observed Frequency - Expected Frequency| = |13 - 10.17| = 2.83
Outcome 12:
|Observed Frequency - Expected Frequency| = |8 - 10.17| = 2.17
The smallest discrepancy corresponds to outcome 2 with a discrepancy of 0.17.
Therefore, the smallest discrepancy between the experimental and expected probabilities in this experiment is 0.17.
First, let's calculate the total number of trials or outcomes:
Total number of trials = 10 + 9 + 6 + 15 + 13 + 8 = 61
The expected probability for each outcome is 1/6 since there are 6 possible outcomes on a fair six-sided die.
The expected frequency for each outcome will be (1/6) * total number of trials (61) = 10.17.
Now, we compare the observed frequencies to the expected frequencies to find the discrepancies:
Outcome 2:
|Observed Frequency - Expected Frequency| = |10 - 10.17| = 0.17
Outcome 4:
|Observed Frequency - Expected Frequency| = |9 - 10.17| = 1.17
Outcome 6:
|Observed Frequency - Expected Frequency| = |6 - 10.17| = 4.17
Outcome 8:
|Observed Frequency - Expected Frequency| = |15 - 10.17| = 4.83
Outcome 10:
|Observed Frequency - Expected Frequency| = |13 - 10.17| = 2.83
Outcome 12:
|Observed Frequency - Expected Frequency| = |8 - 10.17| = 2.17
The smallest discrepancy corresponds to outcome 2 with a discrepancy of 0.17.
Therefore, the smallest discrepancy between the experimental and expected probabilities in this experiment is 0.17.
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