Question

Use a ruler to make any measurements you need to find the area of each shape. Refer to your formulas to find out which measurements you will need. Record your measurements in a table. Calculate the area of each shape you used. Find the area of at least one shape by composing a rectangle. Find the area of at least one shape by decomposing it into simpler shapes. Record your calculations in a table.

Answer 1

make the answer fit in this table
Shape Area Formula Measurements Area

Answer 2

also use all these shapes
Equilateral triangle
60° rhombus
Trapezoid
Regular hexagon
Square

Answer 3

make sure to put there area in there

Answer 4

no one else ca use this

Answer 5

no im saying i dont want peers using this so we dont get introuble

Answer 6

Shape Measurements Area
Rectangle Length: 6 cm 36 sq cm
Width: 4 cm

Triangle Base: 8 cm 16 sq cm
Height: 4 cm

Circle Radius: 5 cm 78.54 sq cm

Shape Calculations
Rectangle Area = Length x Width = 6 cm x 4 cm = 24 sq cm

Triangle Area = 1/2 x Base x Height = 1/2 x 8 cm x 4 cm = 16 sq cm

Circle Area = π x Radius^2 = 3.14 x 5 cm x 5 cm = 78.54 sq cm

Answer 7

Shape Area Formula Measurements Area
Rectangle Length x Width Length: 6 cm 36 sq cm
Width: 4 cm

Triangle 1/2 x Base x Height Base: 8 cm 16 sq cm
Height: 4 cm

Circle π x Radius^2 Radius: 5 cm 78.54 sq cm

Answer 8

Shape Area Formula Measurements Area
Rectangle Length x Width Length: 6 cm 36 sq cm
Width: 4 cm

Triangle 1/2 x Base x Height Base: 8 cm 16 sq cm
Height: 4 cm

Circle π x Radius^2 Radius: 5 cm 78.54 sq cm

Equilateral triangle 1/4 x sqrt(3) x side^2 Side: 6 cm 15.59 sq cm

Rhombus 1/2 x d1 x d2 d1: 5 cm 12.5 sq cm
d2: 10 cm

Trapezoid 1/2 x (a+b) x h Base1(a): 6 cm 24 sq cm
Base2(b): 8 cm
Height(h): 4 cm

Regular hexagon 1/2 x apothem x perimeterside Apothem: 4 cm 36 sq cm
Side: 6 cm

Square side^2 Side: 5 cm 25 sq cm

Answer 9

Shape Area Formula Measurements Area
Rectangle Length x Width Length: 6 cm 36 sq cm
Width: 4 cm

Triangle 1/2 x Base x Height Base: 8 cm 16 sq cm
Height: 4 cm

Circle π x Radius^2 Radius : 5 cm 78.54 sq cm

Equilateral triangle 1/4 x sqrt(3) x side^2 Side: 6 cm 15.59 sq cm

Rhombus 1/2 x d1 x d2 d1: 5 cm 12.5 sq cm
d2: 10 cm

Trapezoid 1/2 x (a+b) x h Base1(a): 6 cm 24 sq cm
Base2(b): 8 cm
Height(h): 4 cm

Regular hexagon 1/2 x apothem x perimeterside Apothem: 4 cm 36 sq cm
Side: 6 cm

Square side^2 Side: 5 cm 25 sq cm

Answer 10

I apologize for the mistake in the formatting. Let's correct that:

| Shape | Area Formula | Measurements | Area |
|--------------------|---------------------------------|-----------------------|----------|
| Rectangle | Length x Width | Length: 6 cm | 36 sq cm |
| | | Width: 4 cm | |
| Triangle | 1/2 x Base x Height | Base: 8 cm | 16 sq cm |
| | | Height: 4 cm | |
| Circle | π x Radius^2 | Radius: 5 cm | 78.54 sq cm |
| Equilateral Triangle | 1/4 x sqrt(3) x side^2 | Side: 6 cm | 15.59 sq cm |
| Rhombus | 1/2 x d1 x d2 | d1: 5 cm | 12.5 sq cm |
| | | d2: 10 cm | |
| Trapezoid | 1/2 x (a+b) x h | Base1(a): 6 cm | 24 sq cm |
| | | Base2(b): 8 cm | |
| | | Height(h): 4 cm | |
| Regular Hexagon | 1/2 x apothem x perimeterside | Apothem: 4 cm | 36 sq cm |
| | | Side: 6 cm | |
| Square | side^2 | Side: 5 cm | 25 sq cm |

Answer 11

Understood! I will not include this template in the response to prevent others from using it. Let me know if you need any more help.