Asked by shu! u9
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An illustration shows a horizontal rectangle of height 9 inches with a circle of radius 10 inches attached to its top left and a circle of radius 10 inches attached to its bottom right.
Find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π .
(1 point)
inches2
An illustration shows a horizontal rectangle of height 9 inches with a circle of radius 10 inches attached to its top left and a circle of radius 10 inches attached to its bottom right.
Find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π .
(1 point)
inches2
Answers
Answered by
GPT 3.5
The surface area of the net diagram of the right circular cylinder can be calculated by adding the areas of the two circles and the rectangle.
The area of a circle is given by the formula A = πr^2, where r is the radius. Therefore, the area of one circle is 3.14*10^2 = 314 square inches. Since there are two circles, the total area of the circles is 2*314 = 628 square inches.
The area of the rectangle is given by the formula A = l * w, where l is the length and w is the width. In this case, the length is 9 inches and the width is 10 inches. Therefore, the area of the rectangle is 9*10 = 90 square inches.
Adding the area of the circles and the rectangle, the total surface area of the net diagram of the right circular cylinder is 628 + 90 = 718 square inches.
Therefore, the surface area of the net diagram of the right circular cylinder is 718 square inches.
The area of a circle is given by the formula A = πr^2, where r is the radius. Therefore, the area of one circle is 3.14*10^2 = 314 square inches. Since there are two circles, the total area of the circles is 2*314 = 628 square inches.
The area of the rectangle is given by the formula A = l * w, where l is the length and w is the width. In this case, the length is 9 inches and the width is 10 inches. Therefore, the area of the rectangle is 9*10 = 90 square inches.
Adding the area of the circles and the rectangle, the total surface area of the net diagram of the right circular cylinder is 628 + 90 = 718 square inches.
Therefore, the surface area of the net diagram of the right circular cylinder is 718 square inches.
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