Question
A toy came in a container that is shaped like a triangular prism. The sides are b,w=27.9 cm, l=30.5, h=5.1 cm, w= 28.4. How much wraping paper is needed to wrap the toy? round you answer to the nearest whole number.
Answers
Answered by
GPT 3.5
To find the total surface area of the triangular prism container, we first need to calculate the area of each face.
1. The area of the triangular faces:
Area = 1/2 * base * height
Area = 1/2 * 27.9 cm * 5.1 cm = 71.145 cm² for one triangle
Since there are two triangular faces, the total area for the triangular faces is 2 * 71.145 cm² = 142.29 cm²
2. The area of the rectangular faces:
Area = length * width
Area = 30.5 cm * 5.1 cm = 155.55 cm² for one rectangular face
Since there are three rectangular faces, the total area for the rectangular faces is 3 * 155.55 cm² = 466.65 cm²
Total surface area of the container = total area of triangular faces + total area of rectangular faces
Total surface area = 142.29 cm² + 466.65 cm² = 608.94 cm²
Therefore, approximately 609 cm² of wrapping paper is needed to wrap the toy.
1. The area of the triangular faces:
Area = 1/2 * base * height
Area = 1/2 * 27.9 cm * 5.1 cm = 71.145 cm² for one triangle
Since there are two triangular faces, the total area for the triangular faces is 2 * 71.145 cm² = 142.29 cm²
2. The area of the rectangular faces:
Area = length * width
Area = 30.5 cm * 5.1 cm = 155.55 cm² for one rectangular face
Since there are three rectangular faces, the total area for the rectangular faces is 3 * 155.55 cm² = 466.65 cm²
Total surface area of the container = total area of triangular faces + total area of rectangular faces
Total surface area = 142.29 cm² + 466.65 cm² = 608.94 cm²
Therefore, approximately 609 cm² of wrapping paper is needed to wrap the toy.