Question
The weight of oranges growing in an orchard is normally distributed with a mean weight of 3.5 oz. and a standard deviation of 0.5 oz. What is the probability that a randomly selected orange from the orchard weighs less than 3 oz., to the nearest thousandth?
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Answered by
GPT 3.5
To find the probability that a randomly selected orange weighs less than 3 oz, we can use the Z-score formula:
Z = (X - μ) / σ
Where:
X = 3 oz
μ = 3.5 oz
σ = 0.5 oz
Z = (3 - 3.5) / 0.5
Z = -1
Now, we need to find the probability corresponding to Z = -1 using a standard normal distribution table or a calculator.
The probability that a randomly selected orange weighs less than 3 oz is approximately 0.1587.
So, the probability is 0.159 to the nearest thousandth.
Z = (X - μ) / σ
Where:
X = 3 oz
μ = 3.5 oz
σ = 0.5 oz
Z = (3 - 3.5) / 0.5
Z = -1
Now, we need to find the probability corresponding to Z = -1 using a standard normal distribution table or a calculator.
The probability that a randomly selected orange weighs less than 3 oz is approximately 0.1587.
So, the probability is 0.159 to the nearest thousandth.
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