Question

The Pyramid is an arena in Memphis, Tennessee. Its height is 321 ft., and its slant height is 436.5 ft. Find the length of the edge of the square base. Round the answer to the nearest tenth.Please help with this problem

Answer 1

incrocect

Answer 2

incorrect

Answer 3

its still incorrect just give me the right asswer

Answer 4

that's incorrect

Answer 5

To find the length of the edge of the square base, we can use the Pythagorean Theorem.

Let the side of the square base be x.

We know that the height of the pyramid is 321 ft and the slant height is 436.5 ft.

Using the Pythagorean Theorem, we have:
x^2 + x^2 = 321^2
2x^2 = 103041
x^2 = 51520.5
x = sqrt(51520.5)
x ≈ 226.9 ft

Therefore, the length of the edge of the square base is approximately 226.9 feet.

Answer 6

I apologize for the mistake in my calculation. Let's correct it.

Let's denote the height of the pyramid as h, the slant height as l, and the length of the edge of the square base as s.

From the information given:
h = 321 ft
l = 436.5 ft

We can set up a right triangle with h, s, and l as the height, the side of the square base, and the slant height respectively. Using the Pythagorean theorem:
s^2 + h^2 = l^2
s^2 + 321^2 = 436.5^2
s^2 + 103041 = 190522.25
s^2 = 87481.25
s ≈ √87481.25
s ≈ 295.7 ft

Therefore, the length of the edge of the square base is approximately 295.7 feet.

Answer 7

I apologize for the mistake in my previous responses. Let's correct the calculation.

Let's denote the height of the pyramid as h, the slant height as l, and the length of the edge of the square base as s.

From the information given:
h = 321 ft
l = 436.5 ft

We can set up a right triangle with h, s, and l as the height, the side of the square base, and the slant height respectively. Using the Pythagorean theorem:
s^2 + (s/2)^2 = l^2
s^2 + (1/4)s^2 = 436.5^2
5/4 s^2 = 436.5^2
s^2 = (436.5^2) * (4/5)
s ≈ √(349875)
s ≈ 591.4 ft

Therefore, the length of the edge of the square base is approximately 591.4 feet.

Answer 8

I apologize for the mistake in my previous responses. Let's calculate the correct answer now.

Let the length of the edge of the square base be x.

Using the Pythagorean Theorem, we have:
(x/2)^2 + 321^2 = 436.5^2
(x^2/4) + 103041 = 190503.25
x^2/4 = 87462.25
x^2 = 349849
x = √349849
x ≈ 591.4 ft

Therefore, the correct length of the edge of the square base is approximately 591.4 feet. Thank you for your patience.

Answer 9

Let's correct the calculation for the length of the edge of the square base of The Pyramid in Memphis, Tennessee.

Given:
Height (h) = 321 ft
Slant height (l) = 436.5 ft

Using the Pythagorean Theorem for a right triangle:
Base^2 + Height^2 = Slant Height^2
Let the edge of the square base be x.

Then:
(x/2)^2 + 321^2 = 436.5^2
(x^2 / 4) + 103041 = 190552.25
x^2 / 4 = 87411.25
x^2 = 349645
x = √349645
x ≈ 591.1 ft

Therefore, the correct length of the edge of the square base is approximately 591.1 feet.